C# Signature:
[DllImport("kernel32.dll", SetLastError=true)]
[PreserveSig]
public static extern uint GetModuleFileName
(
[In]
IntPtr hModule,
[Out]
StringBuilder lpFilename,
[In]
[MarshalAs(UnmanagedType.U4)]
int nSize
);
VB.Net Signature:
<DllImport("kernel32.dll", SetLastError:=True), PreserveSig>
Public Shared Function GetModuleFileName(<[In]> ByVal hModule As IntPtr, <Out()> ByVal lpFilename As StringBuilder, <[In], MarshalAs(UnmanagedType.U4)> ByVal nSize As Integer) As UInteger
End Function
User-Defined Types:
None.
Notes:
None.
Tips & Tricks:
If you want to use GetModuleFilename to retrieve the path the current executable was started from, you should instead consider using System.Windows.Forms.Application.StartupPath. This is a wrapper around GetModuleFilename, so it probably does exactly what you want.
Another way: Process.GetCurrentProcess().MainModule.FileName
Sample Code:
C#
using System;
using System.Text;
using System.Runtime.InteropServices;
using Library.Win32.Process;
namespace Test
{
class Class1
{
[STAThread]
static void Main(string[] args)
{
StringBuilder fileName = new StringBuilder(255);
DllFuntions.GetModuleFileName(IntPtr.Zero, fileName, fileName.Capacity);
Console.WriteLine(fileName);
}
}
}
VB.NET
Dim sbPath As New StringBuilder(255)
GetModuleFileName(IntPtr.Zero, sbPath, sbPath.Capacity)
Debug.Print(sbPath.ToString)
Alternative Managed API:
System.Diagnostics.ProcessModule.FileName or System.Reflection.Module.FullyQualifiedName.
